Solution 00 mL of an aqueous solution of formic acid is titrated with a 0 150 M aqueous solution of NaOH It is found that 21 25 mL of the NaOH solution is Solution mL of an aqueous solution of formic acid is titrated with a M aqueous solution of NaOH It is found thatSolution mL of an aqueous solution of formic acid is titrated with a M aqueous solutionsolution of formic acid is titrated with a M aqueous solution of NaOH It is found that mL of the NaOH solution isSolution mL of an aqueous solution of formic acid is titrated with a Maqueous solution of NaOH It is found that mL of the NaOH solution isSolution mL of an aqueous solution of formic acid is titratedSolution mL of an aqueous
(Solution) 00 mL of an aqueous solution of formic acid is titrated with a 0.150 M aqueous solution of NaOH. It is found that 21.25 mL of the NaOH solution is...
75.00 mL of an aqueous solution of formic acid is titrated with a 0.150 M aqueous solution of NaOH. It is found that 21.25 mL of the NaOH solution is needed to reach the equivalence point. Formic acid has a pKa of 3.74. Calculate the pH when 10.00 mL of the NaOH solution has been added.