Solution 0184 g of a compound of the general formula Cr x NH3 y Cl z was prepared using 3 5246 g CrCl3 H2O 10 0 mL 15 M NH3 It was then analyzed as
Solution g of a compound of the general formula Cr x NH y Cl z was prepared using g CrCl H O mL M
Solution g of a compound of the general formula Cr x NH y Cl z was prepared using
the general formula Cr x NH y Cl z was prepared using g CrCl H O mL M NH It was then analyzed as
Solution g of a compound of the general formula Cr x NH y Cl z
was prepared using g CrCl H O mL M NH It was then analyzed as
Solution g of a compound of the general formula Cr x NH
Solution g of a compound of
(Solution) 0184 g of a compound of the general formula Cr x (NH3) y Cl z was prepared using 3.5246 g CrCl3 * H2O + 10.0 mL 15 M NH3. It was then analyzed as...

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2.0184 g of a compound of the general formula Crx(NH3)yClz was prepared using 3.5246 g CrCl3 * H2O + 10.0 mL 15 M NH3. It was then analyzed as follows: Analysis of Cr3+The concentration of Cr3+ was determined spectrophotometrically. The Cr (III) ion is purple, with a maximum light absorption of 570 nm. A stock solution (Solution 1) of 0.100 M Cr3+ was used to make the following dilutions:Solution 2: 10.00 mL stock solution diluted to total of 100 mL with water Solution 3: 20.00 mL stock solution diluted to a total of 100 mL with water1.2532 g of the unknown chromium compound was dissolved in enough water to make 100 mL of solution. Absorbance readings are given below:Absorbance/Solution #1.850 / 10.187 / 21.122 / 31.122 / unknown compoundCalculate the concentration of Cr3+ in solutions 2 and 3. Then make a graph of absorbance vs. concentration of the chromium compound, calculate moles of Cr3+, grams of cr3+ and %Cr3+ in the unknown compound. Attach graph and show work below.

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