Solution 1 Introduction The derivative of a function f at x is defined in terms of a limit which may be written as f x h f x f x lim h0 h Figure 1
Solution Introduction The derivative of a function f at x is defined in terms of a limit which may be written as f x h f
Solution Introduction The derivative of a function f at x is defined in terms of a limit which may
function f at x is defined in terms of a limit which may be written as f x h f x f x lim h h Figure
Solution Introduction The derivative of a function f at x is defined in terms of a
limit which may be written as f x h f x f x lim h h Figure
Solution Introduction The derivative of a function f at x is defined in
Solution Introduction The derivative of a
(Solution) 1 Introduction The derivative of a function f at x is defined in terms of a limit, which may be written as f(x+h) f(x) f(x) = lim h0 . h Figure 1:...

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Need help with the project see attatchment below, its my first one so im hoping for answers 1 Introduction The derivative of a function f at x is deFned in terms of a limit, which may be written as f ? ( x ) = lim h ? 0 f ( x + h ) ? f ( x ) h . ±igure 1: Graph of the function f ( x )= x x over [0,2]. Layered on top are the tangent line at x =0.6 and two secant lines corresponding to h =1.0 and h =0.5. As h approaches 0, the slope of the secant line approaches the slope of the tangent line. The expression that we take the limit of, f ( x + h ) ? f ( x ) h is interpreted as the slope of the secant line that goes through the points ( x , f ( x )) and ( x + h , f ( x + h )). Then the derivative is interpreted as a slope, in this case of the tangent line , deFned as the limit of the slopes of the secant lines. We've seen that MATLAB can be used to investigate limits. Although, MATLAB doesn't actually Fnd the limit, it suggests an answer by being close to the true answer. In this same way, MATLAB can help us Fnd the value of the derivative of f ( x ) at a single point, and as a function of x (many points at once.) ±igure 1 shows that graph of f ( x )= x x over the interval [0,2] along with three lines which go through the point (0.6, f (0. .6)). The tangent line is drawn to have slope given by f ? ( x ) evaluated at 0.6. The secant lines are drawn to have slope which depends on a speciFed

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